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Excel Vba Instrrev Not Working


Regarding the statement "1 or 2 should give something other than 0" ... Share Share this post on Digg Del.icio.us Technorati Twitter Rick's "mini" blog... There is no '#VALUE!' result waiting for me here. Try MrExcel HTML Maker How To Use MrExcel HTML Maker: http://www.mrexcel.com/forum/about-b...ml#post2545970 Reply With Quote Apr 16th, 2014,04:39 AM #7 Rick Rothstein MrExcel MVP Join Date Apr 2011 Location New Jersey, USA http://intrascol.org/excel-vba/excel-vba-beep-not-working.html

Using InStr() I have been able to locate the end of the email address. Few Important points about Instr function: If anyone of the strings i.e. ‘parent_string’ or ‘substring’ is Null. Therefor with the following address in cell D2 : 1234 S Main St. The easiest way to accomplish this is using a criteria form that a… MS Access Visual Basic Classic MS Access – Writing Solid VBA Code Video by: Jim In Microsoft Access,

Excel Vba Find Position Of Character In String

What is the point of update independent rendering in a game loop? Anyway, I went back to the drawing board and came up with this normally entered formula which seems to work correctly. It is the type of comparison to perform. How to plot a simple circle in LaTeX Can a giant spoon be utilised as a weapon What power do I have as a driver if my interstate route is blocked

  • He is tech Geek who loves to sit in front of his square headed girlfriend (his PC) all day long. :D.
  • at position 17).
  • asked 4 years ago viewed 734 times active 4 years ago Upcoming Events 2016 Community Moderator Election ends in 9 days Related 0VBA string length problem2problems with excel's application.evaluate command in
  • Using vbTextCompare is not the best way: vbTextCompare is not a safe option to use while you are dealing with case-insensitive strings.
  • Then I used InStr() to return the place of the first " " after the @.
  • and I'm frustrated trying to find a way to make this brilliantly clear for you.

Is there a way to block an elected President from entering office? Subscribe to our monthly newsletter for tech news and trends Membership How it Works Gigs Live Careers Plans and Pricing For Business Become an Expert Resource Center About Us Who We For InstrRev you would need to write a UDF. Excel Vba Find Character In String From Left Cert10-23-2002, 07:53 PMlol.

nothing. This makes sense as the 3rd char in "c:\" is a "\". You are calculating starting point and length incorrectly. below is my code.

Related 0Can't save column position changes if .AllowEdits/.AllowDeletions/.AllowAdditions is set1Fields in the wrong order when importing from CSV to Access4When inserting data from a query to a table, does the query Vba Right It is a common requirement that users can specify the criteria for a report at runtime. Thanks Kirsty 0 LVL 84 Overall: Level 84 MS Access 83 Visual Basic Classic 19 Message Active today Expert Comment by:Scott McDaniel (Microsoft Access MVP - EE MVE )2007-11-01 Comment from the end to the start of the string).If the substring is not found, the function returns the value 0.The syntax of the InStrRev function is:InStrRev( StringCheck, StringMatch, [Start], [Compare] )Where

Instrrev Vba

Music notation software for Ubuntu Is there an actual army in 1984? Sorry for making such a blooper! Excel Vba Find Position Of Character In String But I think it is working 'properly', just not like you think it does. Excel Vba Find Character In String From Right The practical use of InStrRev can be in finding the last index of a character inside a string.

substring The substring that you want to find. news I am speculating this works based on my original logic: it would search whats left: 3456789 & thus produced 3 as it still includes the characters before the start position. Since the first two characters of TestString are "12", "3" is not found in that substring, so InStrRev returns 0. I don't know what went wrong here, but I am sure I had this working correctly before I posted it... Excel Vba Left

How can I claim compensation? MS Access Advertise Here 772 members asked questions and received personalized solutions in the past 7 days. No matter if the start begins at left or right, 1 or 2 should give something other than 0. have a peek at these guys Here is the fixed version... =IF(B1="",0,MAX(999-IF(MID(A1,999-ROW($1:$998),LEN(B1))=B1,ROW($1:$998),999))) **Commit this formula using CTRL+SHIFT+ENTER and not just Enter by itself.

The content you requested has been removed. Vba Substring start Optional. Find the position of the last space that occurs within the string "John Michael' Paul Smith" before character 17.Dim pos As Integerpos = InStrRev( "John Michael Paul Smith", "", 17 )'

InStr(4, "Excel-Trick", "c") will result into 10 as here we are starting the search for “c” from the 4th character and hence Instr gives us the position of second “c” (Excel-Trick)

Note: Note the difference in the place of parameters of both InStr and InStrRev functions. compare Optional. the space at position 13.Example 3' Example 3. Excel Instr Formula Not the answer you're looking for?

Instead, you can use the LEN and SUBSTITUTE functions to perform your logical test. Forum Board FAQ Forum Rules Guidelines for Forum Use FAQ Forum Actions Mark Forums Read Quick Links Today's Posts Search New Posts Zero Reply Posts Subscribed Threads MrExcel Consulting Advanced Search Unfortunately InStrRev does not seem to find the true position of the last backslash (effectively the first backslash reading backwards from the end of the path string), it seems to return check my blog Join our community for more solutions or to ask questions.

Then VBA Instr statement returns a Null and hence can cause a code to break. InStrRev(TestString, "3", 2) 0 That statement asked InStrRev to start from the second character in TestString and search backwards for the character "3". Find the position of the last space (i.e. Let me know if you find any anomalies... =IFERROR(FIND(REPT(CHAR(1),LEN(B1)),SUBSTITUTE(A1,B1,REPT(CHAR(1),LEN(B1)),(LEN(A1)-LEN(SUBSTITUTE(A1,B1,"")))/LEN(B1))),0) Actually, it turns out my array-entered** formula also needs a minor modification; one, it needs to protect against the text being searched

Both LSMConsulting and Paul Hews made me aware of my mistake so thank you very much. The syntax of InStrRev is as follows: InStrRev (parent_string, substring, [start], [compare]) Here also the ‘parent_string’ refers to the string within which the ‘substring’ is to be searched. ‘substring’ is the This documentation is archived and is not being maintained. It is also an optional parameter.

How to find x and y coordinates based on the given distance? How does Gandalf end up on the roof of Isengard? I understand InStrRev gives position of last 'matches' (right-to-left) & can comprehend the result when I don't give a start position. Numeric expression setting the one-based starting position for each search, starting from the left side of the string.

I'm guessing here because I never actual used this. but that's not the case. 0 Featured Post What Is Threat Intelligence? This documentation is archived and is not being maintained. If start contains Null, an error occurs.

x = 2 Do Cells(x, 11).Select Cells(x, 11).Value = (InStrRev(Cells(x, 9), Cells(x, 2), " ")) x = x + 1 On Error Resume Next Loop Until Cells(x, 2).Value = "" Where Copyright © 2003-2016 TechOnTheNet.com. Numeric value indicating the kind of comparison to use when evaluating substrings. Join and Comment By clicking you are agreeing to Experts Exchange's Terms of Use.

string vba share|improve this question edited Mar 2 '12 at 16:32 vulkanino 6,94742557 asked Mar 2 '12 at 16:29 user1245523 1 add a comment| 3 Answers 3 active oldest votes up